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8x^2+15x-18000=0
a = 8; b = 15; c = -18000;
Δ = b2-4ac
Δ = 152-4·8·(-18000)
Δ = 576225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{576225}=\sqrt{225*2561}=\sqrt{225}*\sqrt{2561}=15\sqrt{2561}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15\sqrt{2561}}{2*8}=\frac{-15-15\sqrt{2561}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15\sqrt{2561}}{2*8}=\frac{-15+15\sqrt{2561}}{16} $
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